Webcam in the dark, IR

 

Step 3 - Does it work?

Set up your test rig, and let’s get started.

What I did was set up the camera with the filter off and the LED’s next to it, then I took pictures on three painting (© Emile, Pierre and Julia ☺) on a wall about 2m away.

With IR light and the original filter mounted

With IR light and the filter removed

It does work!!! And it works well!

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Related links:

Make an infrared webcam by Barb Dybwad - Describes how you can replace the filter with one that only let IR pass trough.

Commercial IR lightning kits - I found this after I designed my circuit, and they’re doing just the same just on a larger scale.

How to shoot IR - A more serious page about ‘proper’ IR photography.

 

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10 Responses to “Webcam in the dark, IR”

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5. jheiv Says:
   January 11th, 2006 at 21:43

   You are certainly not an electronics engineer.

   (5-(2*1.8)*50=70)??

   Last time I checked this wasn’t true.

   5-180 = -175.

   Oh now I see what you meant. You meant: ((5-(2*1.8))*50=70

   In that case, the reason you multiplied by 50 was because (due to reciprocals) multiplying by 50 is the same as dividing by 0.02 A (or 20 mA). Thus, using Ohm’s law of V=IR or in this case R=V/I where V=1.4 (5 minus the two 1.8V LED voltage drops in series), I=50 Therefore, an appropiate resistor would be a 70 Ohm Resistor.

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7. Freddy K. Says:
   January 26th, 2007 at 17:19

   Here’s a video showing the conversion process of a standard webcam into an infrared cam:

   http://images.metacafe.com/thumb/385098/2760327/4/submitter_catalog/0/transform_your_webcam_into_an_infrared_cam.jpg

   (nice examples of use at the end!)

8. Sebastian Says:
   January 21st, 2008 at 12:27

   Very useful article. Thanks

9. Gopakumar Says:
   November 16th, 2009 at 18:57

   Hey

   Thanks for the info, how ever if i wanted to use a webcam to record combustion efficiency by measuring flame color is it possible?

   Thanks

   Gopu

10. Timothy Says:
    August 18th, 2010 at 0:42

    I’ve always wondered how I can use my webcam in the dark. But, now,that I found this article, my problem is solved!

    Thanks!

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